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Post by efanton on Oct 8, 2019 10:20:52 GMT -5
there's so many way to interpret how the different stanzas contribute to the ten digits of the first key. In fact I think it is worthy of using up one of our valuable monthly questions. Using a question to try determine the make up of the 1st key seems to make sense as a next step.
Personally I think asking the following question would make sense
Does the 5th stanza ultimately contribute 4 digits to the first key?
Personally I don't think this is the case, I suspect stanza 5 generates an 6 or 3 digit number, but the above question would eliminate this idea and many others.
It would also shed some light on the enigma that is stanza 5. The partial solve C4 F5 C6 E6 seems so certain, and is generally accepted, but it would be nice to reinforce or dismiss many of the ideas we have had about stanza 5
Maybe there's a better way to ask this question. I have worded it in the way I did in a effort to get two for the price of one. I am trying to get additional information about the answer from stanza 5 and at the same time get some insight as to the makeup of the first key. Has anyone got a better way of getting the most information out of a single question in relation to the above?
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Post by keladry12 on Oct 8, 2019 13:27:50 GMT -5
Does the 5th stanza ultimately contribute 4 digits to the first key?Personally I don't think this is the case, I suspect stanza 5 generates an 8 digit number, but the above question would eliminate this idea and many others. Can I ask, do you think those 8 digits are all part of the first key and thus the previous stanzas only contribute 2 digits in total, or do you think that these 8 digits then need to have something done to them to get digits that contribute to the key? Or something else?
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Post by efanton on Oct 8, 2019 13:55:21 GMT -5
Does the 5th stanza ultimately contribute 4 digits to the first key?Personally I don't think this is the case, I suspect stanza 5 generates an 8 digit number, but the above question would eliminate this idea and many others. Can I ask, do you think those 8 digits are all part of the first key and thus the previous stanzas only contribute 2 digits in total, or do you think that these 8 digits then need to have something done to them to get digits that contribute to the key? Or something else? At the moment my theory is the following first 3 digits are an area code (from stanza 3) the next digit is a result of stanza 4. I believe stanza 4 will give us a 3 digit number XXX. But we are told 'The next plus two is found, Astride a treasure on its own'. the solve for stanza 4 is 3 digits but we only take the central digit (xXx) the final 6 digits come from stanza 5. C4 F5 C6 E6. Using a keypad this might result in 24352636, but there are many ways of converting C4 F5 C6 E6 to a simple base 10 number It's only an idea that I am kicking around at the moment. The problem is there are probably dozens of other theories out there that could equally match the clues and be equally valid. Without being able to ascertain how many digits of the first key are being contributed by each stanza, any theory is absolutely right until someone either enters a correct number in the key tester or we better understand the format or makeup of the first key. Thats why I suggested the above question. Does the 5th stanza ultimately contribute 4 digits to the first key?Depending on the answer it would give us some insight as to the format of the 1st key, or help us understand what we have to do with the C4 F5 C6 E6 to incorporate that into a solution I could have suggested 'Does the 5th stanza ultimately contribute 6 digits to the first key?', but I assume I am the only person so far to consider that stanza 5 results in 6 digits. I was proposing a question that I assumed would help the most people.
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Post by captnkush on Oct 8, 2019 14:03:33 GMT -5
3424 is kinda what i thinking for stanza 5. (Number of notes in each chord) although im not sure about c6 as its been pointed out its kinda a strange chord with no major or minor .also its the only answer that needs a little streching to fit unlike the other three. Either way to me this is main stanza that needs to be nailed down in order more accurately determine the #. Just thinking in terms of number format . Its not that difficult to either associate a prefix to a area code or vice versa. In both cases you will have less than 999 posibilites.(providing you have a potential solve for either verse) the point is if we get the last 4 digits 100% correct it will greatly limit the possibilities for the prior 6
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Post by efanton on Oct 8, 2019 14:10:44 GMT -5
3424 is kinda what i thinking for stanza 5. (Number of notes in each chord) although im not sure about c6 as its been pointed out its kinda a strange chord with no major or minor .also its the only answer that needs a little streching to fit unlike the other three. Either way to me this is main stanza that needs to be nailed down in order more accurately determine the #. Just thinking in terms of number format . Its not that difficult to either associate a prefix to a area code or vice versa. In both cases you will have less than 999 posibilites.(providing you have a potential solve for either verse) the point is if we get the last 4 digits 100% correct it will greatly limit the possibilities for the prior 6 I agree totally. So how do we ask a question that gives us some insight as to the solve for stanza 5, and, if possible at the same time, get an idea of the format for the first key (or which digits are contributed by each stanza) The obvious solution for stanza 5 would be 4566 or C4 + F5+ C6 + E6 = 365 196 + 245 + 198 + 230 = 869 Giving us only 3 digits. But that seems to be too simplistic in my eyes. But who's to say thats wrong? There's simply too many things that could be done with C4 F5 C6 E6 to produce a simple base 10 number The other thing that our american friends might not be considering is if I want to ring a Dearborn MI phone number it would not start 313 it would start 1331 (more precisely +1313) as 001 or +1 would be the international dial code for the USA
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Post by captnkush on Oct 8, 2019 15:13:21 GMT -5
I have considered the dialing code but personally i think thats a given and wouldnt take that as part of the solve for the ten digit number. Depending on where you're calling from you may need different dialing codes (to exit or enter country of origin)and just about anybody whos ever used a phone should be aware of that. Also i wouldn't necessarily dimiss something just because you feel its too easy. Remember this is one of three stanzas that makes one thing and also c4f5c6e6 still had to be thought up as a solve so to me many(and i stress many because i think anthother simply step or 2 could still be inline) more steps seems unrealisticly difficult for just one part of the key. At least to me . You could be right still. But at least consider what im saying.
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Post by captnkush on Oct 8, 2019 15:23:14 GMT -5
I cant forsee a way lock it down 100% with 1 question. But i think simply asking if c4,f5,c6,and e6 is at least a partial solve for stanza 5 would be a good start.
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Post by efanton on Oct 8, 2019 16:16:53 GMT -5
I cant forsee a way lock it down 100% with 1 question. But i think simply asking if c4,f5,c6,and e6 is at least a partial solve for stanza 5 would be a good start. I was coming to the same conclusion. The problem is those questions are so valuable, and its likely another month goes by without a significant break through. What exactly do we achieve by simply asking if c4,f5,c6,and e6 is at least a partial solve for stanza 5. Ok it would be good to prove what we have so far is right, but with the YES/NO format we still have no idea what to do with the c4,f5,c6,and e6, Ideally we would like to ask how many digits stanza 5 contributes to the 1st key. once we knew how many digits were involved we could then play with the C4 F5 C6 E6 to match that. The problem is with the YES/NO format if we ask does it give a 4 digit answer and that is not correct we are exactly where we are now. What if it was 3, 5 or 6? It would be a wasted question. If we got a YES and knew it was 4 digits then I think that would be more helpful than simply knowing the partial solve was correct. I'm not sure what the next step should be. Do we go for broke and ask does stanza 5 give 4 digits or do we play it safe confirming the C4 F5 C6 E6 and probably be in the same place as we are now in a months time and then use another question to clarify how many digits?
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Post by captnkush on Oct 8, 2019 17:38:29 GMT -5
I sorta feel like with Lukas correcting the missing comma he essentially said its 4 independent ideas. To me that suggests 4 numbers.(of course maybe not) but why bother defining 4 terms otherwise? Honestly i would rather comfirm what we have so far is correct because if even one of those answers is incorrect it sorta puts a kybosh on any other method we might imploy to get a answer.i do hear what you're saying and yes wording is everything but maybe together we can figure out how to ask in a way that would both confirm and point in a direction. Idk im only suggesting this now so we got the whole month to think about it.
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Post by captnkush on Oct 8, 2019 17:49:37 GMT -5
To me the fact that its a tricky one that we have to play carefully does kinda imply a musical connection and while those are all notes they are also all chords how you play them will make a world of difference without necessarily adding a whole lot more steps.
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Post by captnkush on Oct 8, 2019 17:59:52 GMT -5
Also theres at least a few of us who are not totally satisfied with c6 as a answer to no sea legs. While it fits it doesn't quite fit as well as the others .as an answer it needs a little strech to work . The other three answers fit so much better. This fact alone could be a clue to something.
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Post by jewelie on Oct 8, 2019 18:22:49 GMT -5
So, I looked a bit into sea legs. Sea legs basically means that you are able to easily walk on a boat at sea. Well, I was thinking, a place with no sea legs would be the high seas....or high Cs. Now, what do we do with this?
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Post by keladry12 on Oct 8, 2019 19:38:09 GMT -5
So, I looked a bit into sea legs. Sea legs basically means that you are able to easily walk on a boat at sea. Well, I was thinking, a place with no sea legs would be the high seas....or high Cs. Now, what do we do with this? Well, fortunately for us (and rather interestingly), if c6 does refer to a note, that's the note that is commonly called "high c". So, either solution leads to the same place. Nice! 😊
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Post by efanton on Oct 8, 2019 22:08:02 GMT -5
3424 is kinda what i thinking for stanza 5. (Number of notes in each chord) although im not sure about c6 as its been pointed out its kinda a strange chord with no major or minor .also its the only answer that needs a little streching to fit unlike the other three. Either way to me this is main stanza that needs to be nailed down in order more accurately determine the #. Just thinking in terms of number format . Its not that difficult to either associate a prefix to a area code or vice versa. In both cases you will have less than 999 posibilites.(providing you have a potential solve for either verse) the point is if we get the last 4 digits 100% correct it will greatly limit the possibilities for the prior 6 Was interested in your theory, so did a bit of googling www.pianochord.org/C4 C - F - G F5 F - C C6 C - E - G - A E6 E - G# - B - C# that would give 3244. How did you get the 3424?
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Post by captnkush on Oct 9, 2019 1:18:32 GMT -5
3424 is kinda what i thinking for stanza 5. (Number of notes in each chord) although im not sure about c6 as its been pointed out its kinda a strange chord with no major or minor .also its the only answer that needs a little streching to fit unlike the other three. Either way to me this is main stanza that needs to be nailed down in order more accurately determine the #. Just thinking in terms of number format . Its not that difficult to either associate a prefix to a area code or vice versa. In both cases you will have less than 999 posibilites.(providing you have a potential solve for either verse) the point is if we get the last 4 digits 100% correct it will greatly limit the possibilities for the prior 6 Was interested in your theory, so did a bit of googling www.pianochord.org/C4 C - F - G F5 F - C C6 C - E - G - A E6 E - G# - B - C# that would give 3244. How did you get the 3424? omg...sorry to everyone and thank you for catching that. somehow when i copied notes on the subject i must have had a brain fart. Got some of my notes assigned to the wrong chords...(embarrassing) anyway good catch e and thank you.
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